responsum Latin · revision 4360
15 Oct 2026, 22:48 by bogdan “New Latin entry (sources: de Vaan, OLD, Lewis & Short, TLL...)” current version
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+ {{infobox|confidence=established|formation=derivation|attested=Terence|origins=la respondeō}}
+
+ ==Pronunciation==
+ * IPA (Classical): [rɛsˈpõː.sũː]^(Wiktionary)
+ * IPA (Ecclesiastical): [resˈpɔn.sum]^(Wiktionary)
+
+ ==Forms==
+ '''respōnsum''' ''n'' (genitive respōnsī); second declension^(Wiktionary)
+
+ ==Etymology==
+ It is the neuter of the participle of [[respondeo|alt=respondeō]] “to answer”, used as a noun.^(OLD 2012)^(Etymonline) ''Respondeō'' is from [[m|la|re-]] and [[spondeo|alt=spondeō]] “to pledge”.^(Wiktionary)^(Etymonline)
+
+ ==Earliest recorded meaning==
+ Terence uses it of an oracle's answer, saying no reply of Apollo is truer.^(OLD 2012) Köbler dates Terence 190–159 BC.^(Köbler 2010)
+
+ ==Semantic evolution==
+ It was an answer or reply, and one given by a ruler or the senate to envoys, as Cicero says the senate gave Sopater no answer.^(OLD 2012)^(Gaffiot 2016) It was the answer of an oracle or soothsayer, and the opinion of a jurisconsult on a point of law.^(OLD 2012)^(Gaffiot 2016) Livy uses ''respōnsum ferōx'' of a defiant answer.^(Georges 1913)
+
+ In medieval Latin it was a reply in a lawsuit, a defence and the lawsuit itself.^(Niermeyer 1976) English ''response'' is recorded around 1300.^(Etymonline)
+
+ ==Timeline==
+ * 190–159 BC – Terence uses it of an oracle.^(OLD 2012)^(Köbler 2010)
+ * 81–43 BC – Cicero uses it of a reply and of a jurist's opinion.^(OLD 2012)^(Köbler 2010)
+ * c. 1300 – English ''response'' is recorded.^(Etymonline)
+
+ ==Meanings==
+ ===Noun===
+ # An answer, reply, [[m|en|response]].^(OLD 2012)^(Lewis & Short 1879)
+ # The answer of an [[m|en|oracle]] or soothsayer.^(OLD 2012)^(Gaffiot 2016)
+ # A jurist's opinion on a point of law.^(OLD 2012)^(Gaffiot 2016)
+ # ''(Medieval Latin)'' A plea in defence; a lawsuit.^(Niermeyer 1976)
+
+ ==Related words==
+ * [[respondeo|alt=respondeō]]
+ * [[en|response]]
+
+ ==References==
+ {{reflist}}