quocirca Latin · revision 32602
20 Oct 2026, 01:24 by bogdan “Latin la10k batch la75zg b03” current version
Initial text
@@ -0,0 +1,34 @@
+ {{infobox|confidence=established|formation=compound|attested=116–27 BC, Varro|origins=la quī, la circus}}
+
+ ==Pronunciation==
+ * Classical: [kʷoːˈkɪr.kaː]^(Wiktionary)
+ * Ecclesiastical: [kʷoˈt͡ʃir.ka]^(Wiktionary)
+
+ ==Forms==
+ '''quōcircā''' (relative adverb)^(OLD 2012)
+ It is also written as two words, ''quō circā''.^(OLD 2012)^(Lewis & Short 1879)
+
+ ==Etymology==
+ It is [[af|la|quō|circā|t1=by which|t2=around, about]].^(OLD 2012)^(Lewis & Short 1879)^(Wiktionary) De Vaan explains [[m|la|circā]] as a newer form beside [[m|la|circum]], the old accusative of [[m|la|circus|t=circle]], which he takes as probably borrowed from [[grc|κρίκος|tr=kríkos|t=ring]].^(de Vaan 2008)
+
+ ==Earliest recorded meaning==
+ De Vaan dates it from Varro, and Lewis & Short cite his ''De lingua Latina''.^(de Vaan 2008)^(Lewis & Short 1879)^(Köbler 2010) Köbler dates it from Cicero.^(Köbler 2010)
+
+ ==Semantic evolution==
+ It introduces a main sentence: for which reason, wherefore, as when Cicero says that the senate of the ancestors rightly decreed something.^(OLD 2012)^(Lewis & Short 1879) A law inscription also uses it to introduce a clause.^(OLD 2012) Lewis & Short call it rare but classical, and note an old form ⟨quōqirca⟩;^(Lewis & Short 1879) Horace splits it with a word between.^(Lewis & Short 1879) Church Latin glosses it on that account, therefore.^(Stelten 1995)
+
+ ==Timeline==
+ * 116–27 BC – Varro uses it.^(de Vaan 2008)^(Lewis & Short 1879)^(Köbler 2010)
+ * 81–43 BC – Cicero of a decree of the senate.^(Lewis & Short 1879)^(Köbler 2010)
+ * 65–8 BC – Horace splits it with a word between.^(Lewis & Short 1879)^(Köbler 2010)
+
+ ==Meanings==
+ ===Adverb===
+ # For which reason, on which account, [[m|en|wherefore]], therefore.^(OLD 2012)^(Lewis & Short 1879)^(Wiktionary)^(Stelten 1995)
+
+ ==Related words==
+ * [[circa|alt=circā]]
+ * [[idcirco|alt=idcircō]]
+
+ ==References==
+ {{reflist}}